C :

#include<stdio.h>

int leap(int y)
{
	return (y%4==0&&y%100!=0)||(y%400==0);
}

int main()
{
	int M[][2]={0,0,
				31,31,
				28,29,
				31,31,
				30,30,
				31,31,
				30,30,
				31,31,
				31,31,
				30,30,
				31,31,
				30,30,
				31,31};
	int y,m,d,i,j,s;
	while(scanf("%d-%d-%d",&y,&m,&d)!=EOF)
	{
		for(s=i=0;i<y;i++)
			if(leap(i))
				s+=366;
			else
				s+=365;
		for(i=1;i<m;i++)
			if(leap(y))
				s+=M[i][1];
			else
				s+=M[i][0];
		s+=d;
		printf("%d\n",735302-s);
	}
	return 0;
}

C++ :

#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;

struct dat
{
    int year;
    int month;
    int day;
}n,b;

int run(dat a)
{
    if((a.year%4==0&&a.year%100!=0)||a.year%400==0)
        return 1;
    else
        return 0;
}
long long  days(dat a)
{
    long long ans = 0;
    ans = (a.year*365+a.year/4-a.year/100+a.year/400);
    switch (a.month)
    {
        case 12:ans+=30;
        case 11:ans+=31;
        case 10:ans+=30;
        case 9:ans+=31;
        case 8:ans+=31;
        case 7:ans+=30;
        case 6:ans+=31;
        case 5:ans+=30;
        case 4:ans+=31;
        case 3:ans+=28;
        case 2:ans+=31;
        case 1:ans+=a.day;if(run(a)&&(a.month<2||(a.month==2&&a.day==29)))ans--;
    }
    return ans;
}
int main()
{
  //  freopen("in.txt","r",stdin);
    n.year = 2013;
    n.month = 3;
    n.day = 9;
    long long nn,bb;
    nn = days(n);
    while(scanf("%d-%d-%d",&b.year,&b.month,&b.day)!=EOF)
    {
        bb = days(b);
      //  cout<<nn<<" "<<bb<<endl;
        cout<<fabs(nn-bb)<<endl;
    }
}