int main()
{
    int n, m;
    cin >> n >> m;
    int mt, qc;
    qc = (m-n*2)/2;
    mt = n-qc;
    cout << mt << " " << qc;
    return 0;
}

关键代码； 假设全是摩托，则剩下的为汽车

#include using namespace std; const double pi=3.1416; int main() { double r,c,s; scanf("%lf",&r); c=2pir; s=pirr; printf("%.2f\n",c); printf("%.2f\n",s); return 0; }

#include using namespace std; int main() {int n,m,a,b; scanf("%d%d",&n,&m); a=2n-m/2; b=(m-2n)/2; printf("%d %d\n",a,b); return 0; }

#include using namespace std; int main() { int n,m,a,b; scanf("%d%d",&n,&m); a=(4*n-m)/2; b=n-a; printf("%d %d\n",a,b); return 0; }